It can't be done using only five 5s, but using six 5s you can get it: 37 = 555/(5+5+5) it can be done using five 5's (5+5/5) ** 5) + 5 ** = power operation actually the above should be written as: ((5+5)/5)^5 + 5 5!/(5+5) + (5*5) will work also
Five thousand, five hundred respectively.
They are fifty = 50 and five = 5
3.5555 repeating
4x5=20 20x4=80
If: 5s = 33 Then: s = 33/5 = 6.6
It can't be done using only five 5s, but using six 5s you can get it: 37 = 555/(5+5+5) it can be done using five 5's (5+5/5) ** 5) + 5 ** = power operation actually the above should be written as: ((5+5)/5)^5 + 5 5!/(5+5) + (5*5) will work also
5!/(5+5) + (5*5)
The five on the left is ten times the five on the right.
Five thousand, five hundred respectively.
(5 x 5) + (5 x 5) + 5 = 25 + 25 + 5 = 50 + 5 = 55
The five on the left is ten times the five on the right.
They are fifty = 50 and five = 5
3.5555 repeating
5/5=1 Keep this for later. so 2 5s used. Then do 5*5=25, so 5 5s used as 25 has a five in it, now do 1 - 25=24.
The answer is 9C4 = 9*8*7*6/(4*3*2*1) = 126 ways.
4x5=20 20x4=80