You can't tell the perimeter from the area.Here are a few different rectangles and their perimeters.All of them enclose 12 square feet.1/2 x 24 .. . perimeter = 491 x 12 . . . . perimeter = 261.5 x 8 .. . . perimeter = 192 x 6 . . . . . perimeter = 162.4 x 5 .. . . perimeter = 14.83 x 4 . . . . . perimeter = 143.464 x 3.464 . . perimeter = 13.856
A 12' x 24' x 52' pool can hold up to about 112,028 gallons of water.
The perimeter is the distance around, the sum of the sides. A 5 x 7 or a 4 x 8 rectangle has a perimeter of 24.
Let the dimensions be x and y:- Perimeter: 2(x+y) = 24 => x+y = 12 => y = 12-x Area: xy = 32 => x(12-x) = 32 => 12x-x2-32 = 0 Solving the above quadratic equation gives x = 4 and x = 8 Therfore the dimensions of the rectangle are 4 units by 8 units Check: 2(4+8) = 24 units and 4*8 = 32 square units
http://www.havuz.org/pool-calculators.htm try this link
12 x 24
to get the perimeter you take 12 x 2 and 22 x 2 get those numbers then add them and you have your perimeter
You can't tell the perimeter from the area.Here are a few different rectangles and their perimeters.All of them enclose 12 square feet.1/2 x 24 .. . perimeter = 491 x 12 . . . . perimeter = 261.5 x 8 .. . . perimeter = 192 x 6 . . . . . perimeter = 162.4 x 5 .. . . perimeter = 14.83 x 4 . . . . . perimeter = 143.464 x 3.464 . . perimeter = 13.856
12 x 24 oval
12+12=24 8+8= +16 The perimeter =40cm2
A 12' x 24' x 52' pool can hold up to about 112,028 gallons of water.
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
The perimeter is the distance around, the sum of the sides. A 5 x 7 or a 4 x 8 rectangle has a perimeter of 24.
Let the length be x-12 and the width be x: 2(length+width) = perimeter 2(x-12+x) = 240 2x-24+2x = 240 4x = 240+24 4x = 264 x = 66 Therefore: length = 54 feet and width = 66 feet
Let the dimensions be x and y:- Perimeter: 2(x+y) = 24 => x+y = 12 => y = 12-x Area: xy = 32 => x(12-x) = 32 => 12x-x2-32 = 0 Solving the above quadratic equation gives x = 4 and x = 8 Therfore the dimensions of the rectangle are 4 units by 8 units Check: 2(4+8) = 24 units and 4*8 = 32 square units
http://www.havuz.org/pool-calculators.htm try this link
Perimeter= 2length x 2widthSince the perimeter is 40 and 2 times the width is 16, that means 2 times the length is 24. The length is 12.