Let the dimensions be x and y:-
Perimeter: 2(x+y) = 24 => x+y = 12 => y = 12-x
Area: xy = 32 => x(12-x) = 32 => 12x-x2-32 = 0
Solving the above quadratic equation gives x = 4 and x = 8
Therfore the dimensions of the rectangle are 4 units by 8 units
Check: 2(4+8) = 24 units and 4*8 = 32 square units
32
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
The answer is Length 4 and Width -8.
The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
To find the least perimeter of a rectangle with a fixed area of 32 square feet, we can use the relationship between area and perimeter. For a rectangle, the area ( A = l \times w ) (length times width) and the perimeter ( P = 2(l + w) ). To minimize the perimeter while keeping the area constant, the rectangle should be a square. The side length of a square with an area of 32 ft² is ( \sqrt{32} ), which is approximately 5.66 ft. Thus, the least perimeter is ( 4 \times \sqrt{32} ), which is approximately 22.63 ft.
32
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
The answer is Length 4 and Width -8.
If you restrict yourself to integers, the answer is 24 feet.
area 63 and perimeter is 32
A square with a perimeter of 32 inches has an area of 64 square inches.
length----8cm breadth---4cm
The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
To find the least perimeter of a rectangle with a fixed area of 32 square feet, we can use the relationship between area and perimeter. For a rectangle, the area ( A = l \times w ) (length times width) and the perimeter ( P = 2(l + w) ). To minimize the perimeter while keeping the area constant, the rectangle should be a square. The side length of a square with an area of 32 ft² is ( \sqrt{32} ), which is approximately 5.66 ft. Thus, the least perimeter is ( 4 \times \sqrt{32} ), which is approximately 22.63 ft.
32
Perimeter: 32 m Area: 60 m
You can't tell. The area doesn't tell the dimensions or perimeter.If the rectangle's area is 32 square inches, here are ten different perimeters that it could have.ALL of these have 32 square inches of area, and there are many, many more:0.8 x 40 . . . . . . Perimeter = 81.6 inches1 x 32 . . . . . . . Perimeter = 66 inches1.25 x 25.6 . . . Perimeter = 53.7 inches1.6 x 20 . . . . . . Perimeter = 43.2 inches2 x 16 . . . . . . . Perimeter = 36 inches2.5 x 12.8 . . . . Perimeter = 30.6 inches3.2 x 10 . . . . . Perimeter = 26.4 inches4 x 8 . . . . . . . Perimeter = 24 inches5 x 6.4 . . . . . Perimeter = 22.8 inches51/3 x 6 . . . . Perimeter = 222/3 inches