Let the dimensions be x and y:-
Perimeter: 2(x+y) = 24 => x+y = 12 => y = 12-x
Area: xy = 32 => x(12-x) = 32 => 12x-x2-32 = 0
Solving the above quadratic equation gives x = 4 and x = 8
Therfore the dimensions of the rectangle are 4 units by 8 units
Check: 2(4+8) = 24 units and 4*8 = 32 square units
32
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
The answer is Length 4 and Width -8.
The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
32
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
The answer is Length 4 and Width -8.
area 63 and perimeter is 32
If you restrict yourself to integers, the answer is 24 feet.
A square with a perimeter of 32 inches has an area of 64 square inches.
length----8cm breadth---4cm
The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
32
Perimeter: 32 m Area: 60 m
When the area of a square is 36cm2, its perimeter is: 24 cm
You can't tell. The area doesn't tell the dimensions or perimeter.If the rectangle's area is 32 square inches, here are ten different perimeters that it could have.ALL of these have 32 square inches of area, and there are many, many more:0.8 x 40 . . . . . . Perimeter = 81.6 inches1 x 32 . . . . . . . Perimeter = 66 inches1.25 x 25.6 . . . Perimeter = 53.7 inches1.6 x 20 . . . . . . Perimeter = 43.2 inches2 x 16 . . . . . . . Perimeter = 36 inches2.5 x 12.8 . . . . Perimeter = 30.6 inches3.2 x 10 . . . . . Perimeter = 26.4 inches4 x 8 . . . . . . . Perimeter = 24 inches5 x 6.4 . . . . . Perimeter = 22.8 inches51/3 x 6 . . . . Perimeter = 222/3 inches