Let the dimensions be x and y:-
Perimeter: 2(x+y) = 24 => x+y = 12 => y = 12-x
Area: xy = 32 => x(12-x) = 32 => 12x-x2-32 = 0
Solving the above quadratic equation gives x = 4 and x = 8
Therfore the dimensions of the rectangle are 4 units by 8 units
Check: 2(4+8) = 24 units and 4*8 = 32 square units
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32
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
The answer is Length 4 and Width -8.
The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm