Let the length be x and the width is 20:-
2(x+20) = 110
2x+40 = 110
Subtract 40 from both sides and then divide both sides by 2 to find the width:-
x = 35 feet which is the length
Check: 2(35+20) = 110 feet which is the perimeter
A 6 by 4 rectangle will have a perimeter of 20 units
20
Perimeter = 20+8+20+8 = 56 cm.....
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Length: 4; Width: 5 or Length: 5; Width: 4
A 6 by 4 rectangle will have a perimeter of 20 units
20
The width of the rectangle is 4 cm
Perimeter = 20+8+20+8 = 56 cm.....
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
20 cm
30
30 ft
Length: 4; Width: 5 or Length: 5; Width: 4
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
21cm3