(9+5+5+1+1) x 1
Working on the .21 only. There are 2 digits in 21. The 1 is in the 100th decimal place.So .21 is also 21/100 which gives a final answer of 6 21/100
3.14159265358979323846
One possible solution is: 4.4 + 4 / .4 = 21
You can make: 1 combination containing 0 digits, 7 combinations containing 1 digits, 21 combinations containing 2 digits, 35 combinations containing 3 digits, 35 combinations containing 4 digits, 21 combinations containing 5 digits, 7 combinations containing 6 digits, and 1 combinations containing 7 digits. That makes 2^7 = 128 in all.
Yes, but only if there are no digits after the decimal point. For example, 18, 19, 20, 21 are consecutive numbers in the decimal system.
Try the different numbers - there are only 11 after all - and multiply their digits. Or analyze the factors of the number 21.
Any number using each of the digits once will be a multiple of 3: eg 1597864302
42/40 = 21/20 or 11/20
Working on the .21 only. There are 2 digits in 21. The 1 is in the 100th decimal place.So .21 is also 21/100 which gives a final answer of 6 21/100
3.14159265358979323846
To get 900 using the digits 1 to 9 without repetition, you can multiply 9 by 100. This is because 9 times 100 equals 900. By using the digit 9 once and the digit 1 twice, you can achieve the desired result without repeating any digits.
21
There are 9 pages with a single digit (pages 1-9) = 9 digits There are 30 - 9 = 21 pages with two digits = 21 × 2 = 42 digits → There are 9 + 41 = 51 digits in total.
You can abbreviate the year in a formal document by using the last two digits of the year preceded by an apostrophe, such as '21 for the year 2021.
One possible solution is: 4.4 + 4 / .4 = 21
2+3=5... 5x4=20... 20+1=21 !
You can make: 1 combination containing 0 digits, 7 combinations containing 1 digits, 21 combinations containing 2 digits, 35 combinations containing 3 digits, 35 combinations containing 4 digits, 21 combinations containing 5 digits, 7 combinations containing 6 digits, and 1 combinations containing 7 digits. That makes 2^7 = 128 in all.