I presume each number can be used once only.
3 + (4 x 5/10) = 3 + 2 = 5
4/.4 + 4/4 = 10 + 1 = 11.
10 raised to power 4
(3x4+5+6+7)/10=3
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
can do it without using the 3, is that allowed? 4 x 6 x 10 = 240 + 6 + 8 = 254
1 - 1/4get common denominators4/4 - 1/4subtract the top numbers3/4
Many ways, but one example is: 4+4+(4/4)+(4/4)= 10.
The closest you can get by: Using Each Number Once With Powers: 10 th the second power - 4 th the third power=46 Using each Number Once Without Powers:(4*10)-3+2 Using an indefinite amount of each number:4-*10+(3*2)-(2+2+2)
4/.4 + 4/4 = 10 + 1 = 11.
3 - 4 + 5 * 6 + 7 > 10
10 raised to power 4
9+1-4(2) 10-8=2
(3x4+5+6+7)/10=3
6*(9 + 5 - 10) = 6*(14 - 10) = 6*4 = 24
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
To get the number 10 using only four fours, you can use the following mathematical expression: (4 + 4) + (4 / 4) = 10. This expression breaks down as follows: first, add 4 and 4 to get 8. Then, divide 4 by 4 to get 1. Finally, add 8 and 1 to get 10. This solution utilizes basic arithmetic operations creatively to achieve the desired outcome.
can do it without using the 3, is that allowed? 4 x 6 x 10 = 240 + 6 + 8 = 254