2 and 40 4 and 10
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
40 can be divided by 1, 2, 4, 5, 8, 10, 20, 40.
All numbers that are multiples of all 2, 8 & 10 are multiples of their lowest common multiple which is 40.The multiples of 40 are 40, 80, 120, 160, ... of which only 80 is between 61 and 107.
There are infinite numbers, but 10 is a factor of 20,30, 40, 50, etc.
10 x 8 = 80 ÷ 2 = 40 + 7 = 47
2 and 40 4 and 10
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
All numbers, except these: 1, 2, 4, 5, 8, 10, 20, 40.
numbers which are divisible by 5, 10 and 2: 10, 20, 30, 40, 50, ...prime factorization of:5 = ..510 = 5 x 22 =........2=======LCM=5 x 2 = 10Multiples of 10 are numbers which are divisible by 5, 10 and 2: 10, 20, 30, 40, 50, ...
10 and 4 10x4 =40 10-4 +6
Factors of 40 are numbers that, when multiplied in pairs give the product as 40. There are 8 factors of 40, which are 1, 2, 4, 5, 8, 10, 20 and 40. Here, 40 is the biggest factor. The Prime Factors and Pair Factors of 40 are 1, 2, 4, 5, 8, 10, 20, 40 and (1, 40), (2, 20), (4, 10) and (5, 8) respectively. Hope that helped!
40 and 50
1, 2, 4, 5, 8, 10, 20, 40.
1, 2, 4, 5, 8, 10, 20, 40
40 is divisible by 1, 2, 4, 5, 8, 10, 20, 40.
1*40 2*40 4*10 5*8