Oh, dude, you want me to find 4-digit numbers where the digits add up to 2? That's like finding a needle in a haystack! But hey, I'm up for the challenge. The only number that fits the bill is 1001. So, there you go, one lonely 4-digit number with a digit sum of 2.
Let's go through the process: Add 1 to 456: 456 1 = 457 456+1=457 (does not contain the digit 4) Add 2 to 456: 456 2 = 458 456+2=458 (does not contain the digit 4) Add 3 to 456: 456 3 = 459 456+3=459 (does not contain the digit 4) Add 4 to 456: 456 4 = 460 456+4=460 (contains the digit 4) Here, adding 4 gives us 460, which includes the digit 4. Therefore, the smallest number you can add to 456 to get a sum that uses the digit 4 is 4 4 Read More...tinyurl .com/sx3dkfpw
1002 = 10000 which is the smallest possible 5 digit number. So we have to go 1 smaller which is 992 = 9801
No. To be divisible by 6 the number must be divisible by both 2 and 3. To be divisible by 2, the last digit of the number must be even (ie one of {0, 2, 4, 6, 8}). The last digit of 35 is 5 which is not even and so 35 is not divisible by 2. To be divisible by 3, sum the digits of the number and if this sum is divisible by 3 then so is the original number. As the test can be applied to the sum, repeatedly summing the digits of the sums until a single digit remains, then the original number is divisible by 3 only if this single digit is one of {3, 6, 9}. For 35 3 + 5 = 8 which is not divisible by 3 (nor is is one of {3, 6, 9}, thus 35 is not divisible by 3. As 35 is not divisible by both 2 and 3 (in fact it is divisible by neither 2 nor 3) it is not divisible by 6.
100
Oh, dude, you want me to find 4-digit numbers where the digits add up to 2? That's like finding a needle in a haystack! But hey, I'm up for the challenge. The only number that fits the bill is 1001. So, there you go, one lonely 4-digit number with a digit sum of 2.
The smallest whole number where the sum of the digits is 21 is 189. This number has a digit sum of 1+8+9 = 18. To find the smallest number with a digit sum of 21, we need to increase the hundreds digit by 1 and decrease the units digit by 1, resulting in 198.
Well I believe that when you divide the number 1st you have to see if the number will go in to the three digit number and if don't then see if another can go into that one
The formula for finding the sum of interiors angles is... S(sum) = 180(n(number of sides) -2) S = 180(n-2) so... S = 180(35 - 2) S = 180(33) S = 5940 And there you go!
Let's go through the process: Add 1 to 456: 456 1 = 457 456+1=457 (does not contain the digit 4) Add 2 to 456: 456 2 = 458 456+2=458 (does not contain the digit 4) Add 3 to 456: 456 3 = 459 456+3=459 (does not contain the digit 4) Add 4 to 456: 456 4 = 460 456+4=460 (contains the digit 4) Here, adding 4 gives us 460, which includes the digit 4. Therefore, the smallest number you can add to 456 to get a sum that uses the digit 4 is 4 4 Read More...tinyurl .com/sx3dkfpw
1002 = 10000 which is the smallest possible 5 digit number. So we have to go 1 smaller which is 992 = 9801
No. To be divisible by 6 the number must be divisible by both 2 and 3. To be divisible by 2, the last digit of the number must be even (ie one of {0, 2, 4, 6, 8}). The last digit of 35 is 5 which is not even and so 35 is not divisible by 2. To be divisible by 3, sum the digits of the number and if this sum is divisible by 3 then so is the original number. As the test can be applied to the sum, repeatedly summing the digits of the sums until a single digit remains, then the original number is divisible by 3 only if this single digit is one of {3, 6, 9}. For 35 3 + 5 = 8 which is not divisible by 3 (nor is is one of {3, 6, 9}, thus 35 is not divisible by 3. As 35 is not divisible by both 2 and 3 (in fact it is divisible by neither 2 nor 3) it is not divisible by 6.
No, it does not. It is finding a number that they all go into evenly.
100
Yes. It goes in 188 times. --------------------------------------- To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 564 this gives: 564 → 5 + 6 + 4 = 15 15 → 1 + 5 = 6 6 is one of {3, 6,9} so 564 is divisible by 3.
no, numbers go up to infinity and down to negative infinity.
If the last digit is a 5-9 you round up. Ex: 585 go up to 590. If the last digit is 1-4 you round down ex: 584 go down to 580