The easy way is to plot the x- and y-intercept points and draw the lines that passes through those two points.
If y = 0, then we have 3x = -2and x = -2/3. So the x-intercept point is (-2/3, 0).
If x = 0, then we have -y = -2and y = 2. So the y-intercept point is (0, 2).
Plot the points and draw the line.
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
yes 3xy=6
-2
(x + 6y)(x - 3y)
Whooop!
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
x = -1 y = 2 2x3 - 3xy = 2 (-1)3 - 3(-1)(2) = 2 (-1) - (-6) = -2 + 6 = 4 Suggestion: Please be careful around problems like this until you have some more experience.
no
No, it is not.
2(2)2 + 3(2)(- 4) - 4(- 4)2 8 - 24 - 64 = - 80 ======
18x3y5 + 9xy3 - 3xy = 3xy(6x2y4 + 3y2 - 1)
yes 3xy=6
3xy - 3xy = 0
-2
(x + 6y)(x - 3y)
Any graph with the slope of -1/2
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.