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How do you graph a polynomial in order to solve for the Zeros?
SeanMcNelis
Either graph the polynomial on graph paper manually or on a graphing calculator.
If it is a "y=" polynomial, then the zeroes are the points or point where the polynomial touches the x-axis.
If it is an "x=" polynomial, then the zeroes are the points or point where the polynomial touches the y-axis.
If it touches neither, then it has no zeroes.
Wiki User
∙ 11y ago
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How do you find zeros of a polynomial?
If there is one variable. Then put each variable equal to zero and then solve for the other variable.
What would you do if the equation had x squared or x cubed in the polynomial equation?
It depends on what you wanted to do - graph it, solve it, factorise it, etc.
In what form must a polynomial equation occur in order to solve?
Standard Form
Division of polynomial by a polynomial?
Can be done.
What does it mean to solve a polynomial?
Find values of the variable for which the value of the polynomial is zero.
What are the values at which the graph of a polynomial crosses the x-axis?
The graph of a polynomial in X crosses the X-axis at x-intercepts known as the roots of the polynomial, the values of x that solve the equation.(polynomial in X) = 0 or otherwise y=0
How do you find zeros of a polynomial?
If there is one variable. Then put each variable equal to zero and then solve for the other variable.
How do you do a parabola?
A parabola is a graph of a 2nd degree polynomial function. Two graph a parabola, you must factor the polynomial equation and solve for the roots and the vertex. If factoring doesn't work, use the quadratic equation.
What would you do if the equation had x squared or x cubed in the polynomial equation?
It depends on what you wanted to do - graph it, solve it, factorise it, etc.
In what form must a polynomial equation occur in order to solve?
Standard Form
Division of polynomial by a polynomial?
Can be done.
How do you answer polynomial?
You can evaluate a polynomial, you can factorise a polynomial, you can solve a polynomial equation. But a polynomial is not a specific question so it cannot be answered.
What does it mean to solve a polynomial?
Find values of the variable for which the value of the polynomial is zero.
3x plus 6y equals 48?
You could graph this Polynomial by using substution to solve for two points..which will define a line. If x=16, then y=0, If x=0, then y=8. Graph this line and you have the solution set for the equation.
How do you solve this For a polynomial of degree n express the coefficient of x to the n-1 power and the constant coefficient in terms of the zeros of the polynomial?
If the roots are r1, r2, r3, ... rn, then coeff of x^(n-1) = -(r1+r2+r3+...+rn) and constant coeff = (-1)^n*r1*r2*r3*...*rn.
How do you solve this equation Form a polynomial with the given zeros 2 mult 2 3 5 I don't want the answer I want to know how to find the answer?
If you have the zeros of a polynomial, it is easy, almost trivial, to find an expression with those zeros. I am not sure I understood the question correctly, but let's assume you have the zero 2 with multiplicity 2, and other zeros at 3 and 5. Just write the expression: (x-2)(x-2)(x-3)(x-5). (Example with a negative zero: if there is a zero at "-5", the factor becomes (x- -5) = (x + 5).) You can multiply this out to get the polynomial if you like. For example, if you multiply every term in the first factor with every term in the second factor, you get x2 -2x -2x + 4 = x2 -4x + 4. Next, multiply each term of this polynomial with each term of the next factor, etc.
Why the graph of a polynomial function with real coefficients must have a y-intercept but may have no x-intercept?
For a polynomial of the form y = p(x) (i.e., some polynomial function of x), having a y-intercept simply means that the polynomial is defined for x = 0 - and a polynomial is defined for any value of "x". As for the x-intercept: from left to right, a polynomial of even degree may come down, not quite reach zero, and then go back up again. A simple example is y = x2 + 1. Why is the situation for "x" and for "y" different? Well, the original equation is a polynomial in "x"; but if you solve for "x", you don't get a polynomial in "y".
