y = x + 4
Solve for the y intercept (when x = 0)
y = (0) + 4
y = 4
So we have one coordinate: (0,4)
Now solve another point, let's make y 0:
0 = x + 4
x = -4
So we have a second coordinate: (-4, 0)
Plot those two points on the graph, and draw a line connecting them. The line additionally is keeps going past those points on both sides, unless it is bounded by a restriction -- in this case it is not.
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the graph is moved down 6 units
The graph of that equation is a circle, centered at the origin, with radius = 2 .
The slope of the line that represents the graph of that equation is 15.
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
y=x+4 To graph this, you need to find the y-intercept in the equation which is 4. Plot that on the graph by going up 4 from the origin (0,0). Next, go right one, up one and plot. Then, right one, up one again.