0
y = x + 4
Solve for the y intercept (when x = 0)
y = (0) + 4
y = 4
So we have one coordinate: (0,4)
Now solve another point, let's make y 0:
0 = x + 4
x = -4
So we have a second coordinate: (-4, 0)
Plot those two points on the graph, and draw a line connecting them. The line additionally is keeps going past those points on both sides, unless it is bounded by a restriction -- in this case it is not.
I'll include a link to site that let's you check your work in the related links.
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What is the effect on the graph of the equation y equals x2 plus 2 when it is changed to y equals x2 - 4?
the graph is moved down 6 units
What is the slope of the following equation y equals 15 x plus 4?
The slope of the line that represents the graph of that equation is 15.
X2 plus y2 equals 4?
The graph of that equation is a circle, centered at the origin, with radius = 2 .
How many solutions are in x2 plus x plus 4 equals 0?
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
How do you graph equation y equals x plus 4?
y=x+4 To graph this, you need to find the y-intercept in the equation which is 4. Plot that on the graph by going up 4 from the origin (0,0). Next, go right one, up one and plot. Then, right one, up one again.
How do you graph the equation yx plus 4?
That's not an equation, so there's nothing to graph. Simple way to tell: There's no "equals" sign in it.
What is the effect on the graph of the equation y equals x2 plus 2 when it is changed to y equals x2 - 4?
the graph is moved down 6 units
What is the slope of the following equation y equals 15 x plus 4?
The slope of the line that represents the graph of that equation is 15.
X2 plus y2 equals 4?
The graph of that equation is a circle, centered at the origin, with radius = 2 .
Which equation has the steepest graph y equals 7x plus 3 y equals -2x plus 6 y equals -10x - 4 y equals 8x - 1?
y=-10x-4
How many solutions are in x2 plus x plus 4 equals 0?
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
How do you graph equation y equals x plus 4?
y=x+4 To graph this, you need to find the y-intercept in the equation which is 4. Plot that on the graph by going up 4 from the origin (0,0). Next, go right one, up one and plot. Then, right one, up one again.
What is the solution for the equation -x plus y equals 4 and the equation 2x plus y equals 4?
x = 0 and y = 4
Sketch the graph for equation x plus y equals 5?
It's equal to -X + 5 = Y (1, 4) (5, 0)
Graph of a system of linear equations. Equation 1 is x minus y equals negative 6. Equation 2 is 5x plus 3y equals 24?
-2x=2y-4 2x-y=-5 Answer=(-1,3)
How do you graph the equation x squared plus y squared equals 16?
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
What is the graph of the equation y equals x translated 4 units up?
It is y = x + 4
