y = x + 4
Solve for the y intercept (when x = 0)
y = (0) + 4
y = 4
So we have one coordinate: (0,4)
Now solve another point, let's make y 0:
0 = x + 4
x = -4
So we have a second coordinate: (-4, 0)
Plot those two points on the graph, and draw a line connecting them. The line additionally is keeps going past those points on both sides, unless it is bounded by a restriction -- in this case it is not.
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the graph is moved down 6 units
The slope of the line that represents the graph of that equation is 15.
The graph of that equation is a circle, centered at the origin, with radius = 2 .
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
y=x+4 To graph this, you need to find the y-intercept in the equation which is 4. Plot that on the graph by going up 4 from the origin (0,0). Next, go right one, up one and plot. Then, right one, up one again.