The square root of x12 is x6 .
√(40 x12y9) = 6.3246√(y)* x6 *y4 or 6.3246x6y4.5 ■
A graph of a ^2 looks like a capital "U" and a graph of a ^3 looks like "U" but the left side of the "U" is flipped over the x-axis.
a hill
doesn't exist
The square root of x12 is x6 .
To take the square root of any power, just reduce the exponent to one-half of each value.
√(40 x12y9) = 6.3246√(y)* x6 *y4 or 6.3246x6y4.5 ■
A graph of a ^2 looks like a capital "U" and a graph of a ^3 looks like "U" but the left side of the "U" is flipped over the x-axis.
a hill
I think you've left out something. Is one of the "x" functions squared?
y = (square root 1- x2) + (cube root x2)
doesn't exist
Graph doesn't have a root word. Graph IS a root word darling.
It is a value that cannot be described by the traditional (x,y) graph due to a negative square root and is designated by a cursive i, which stands for the square root of (-1).
Providing that it is a right angle then use Pythagoras' theorem:- 32+62 = 45 and the square root of this is the hypotenuse which is about 6.708203932
If it asks for the opposites, then add a negative.