Q: How do you graph x minus y equals 4 and x minus 3y equals 4?

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4x - 3y = 12-3y = -4x + 12y = (4/3)x - 4^plug this transformed version of the equation into your graphing calculator or do it out by hand.

(4, -7)

If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1

Normally, this is a difficult form of the equation to deal with. To change it into a more familiar form, we can do this: 4x + 3y = 0 3y = -4x y = (-4/3)x

What is the slope-intercept form of 7x-3y equals 4

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4x - 3y = 12-3y = -4x + 12y = (4/3)x - 4^plug this transformed version of the equation into your graphing calculator or do it out by hand.

-2x=2y-4 2x-y=-5 Answer=(-1,3)

(4, -7)

-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4

2x + 3y = 29x= 4 find x 29x= 4 x = (4/29) sub x into the first part of the sum 2x + 3y = 4 2*(4/29) + 3y = 4 note * means multiply (8/29) + 3y = 4 3y = 4 - (8/29) 3y = (108/29) note 4* 29 minus 8 = 108 y = (36/29) there is probably a quicker way to do this.

{-1,-2}

If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1

4.34684352143

Normally, this is a difficult form of the equation to deal with. To change it into a more familiar form, we can do this: 4x + 3y = 0 3y = -4x y = (-4/3)x

4x - 3y = -6Add 3y to each side:4x = -6 + 3yAdd 6 to each side:4x + 6 = 3yDivide each side by 3:(4/3)x + 2 = yThe graph is a straight line with a slope of (4/3) and a y-intercept of 2 .

What is the slope-intercept form of 7x-3y equals 4

6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)