Always begin by putting your equations in slope intercept form:
x + y = 5
y = -x +5
By plugging numbers in for x, we can solve for y - we can easily find two points for this line: (0,5) and (5,0)
2x - y = 1
-y = -2x + 1
y = 2x - 1
Again, we can now easily find two points for this line: (0,-1) and (2,3)
-2x plus 3y equals 1
No. But sin2a equals 1 minus cos2a ... and ... cos2a equals 1 minus sin2a
1 plus 1 plus 1 plus 1 equals 1 times 4. 1 times 4 equals 4. 4 minus 4 equals 0. 0
The equation is y=x(x+1)(x-2)2
13...... 9 plus 5 equals 14...... 14 minus 1 equals 13
y=x+1 there for answer is 2
-2x plus 3y equals 1
One
No. But sin2a equals 1 minus cos2a ... and ... cos2a equals 1 minus sin2a
1 plus 1 plus 1 plus 1 equals 1 times 4. 1 times 4 equals 4. 4 minus 4 equals 0. 0
The equation is y=x(x+1)(x-2)2
It equals 1
A = 6
13...... 9 plus 5 equals 14...... 14 minus 1 equals 13
1 plus 1 equals one fact
Yes
A graph that has 1 parabolla that has a minimum and 1 positive line.