0
To graph the equation ( y = 10 ), draw a horizontal line across the y-axis at the point where ( y ) equals 10. This line will extend infinitely in both directions along the x-axis, as the value of ( y ) remains constant at 10 regardless of ( x ). Each point on this line will have the coordinates ( (x, 10) ) for any value of ( x ).
What else can I help you with?
How do you work out -5x-10 10 solving what y equals?
To work out y=-5x-10 you can plot a graph.
This is a graph of y equals 5x - 10?
-5
What happens to the graph of y equals x when the equation changes to y equals x - 9?
The graph shifts downward (negative y) by 9 units.
What describes how to translate the graph of y equals x to obtain the graph of y equals x plus 1 - 2?
3
Graph y equals 8x-2?
10
How do you work out -5x-10 10 solving what y equals?
To work out y=-5x-10 you can plot a graph.
What describes the translation of the graph of y equals x2 to obtain the graph of y equals -x2 - 3?
No translation will invert a quadratic graph.
This is a graph of y equals 5x - 10?
-5
What happens to the graph of y equals x when the equation changes to y equals x - 9?
The graph shifts downward (negative y) by 9 units.
What is the transformation of the graph of y equals x2 to obtain the graph of y equals -x2 plus 3?
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
Graph the line y equals 5?
y= -5
What describes how to translate the graph of y equals x to obtain the graph of y equals x plus 1 - 2?
3
What describes how to translate the graph y equals x to obtain the graph of y equals x plus 1 plus 1?
y=x+1 there for answer is 2
How can you translate the graph of y equals x to obtain the graph of y equals x-4 plus 2?
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
Graph y equals 8x-2?
10
What is y equals 8-2x?
10
State the y-intercept for the graph y equals -4x?
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
