Find x when y = 0
0 = -3x + 4 so 3x = 4 or x = 4/3
Mark the point (4/3, 0).
Find y when x = 0
y = 0 + 4 so y = 4
Mark the point (0, 4)
Join the above two points and extend the line in both directions.
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The line of the graph satisfies the equation y = 3x + 4, a linear equation. In other words, the graph will be a straight line. For x = 0 follows that y = 4: the y-intercept is 4. This gives one point (0, 4).
The gradient (or 'slope') is 3. Thus, move one unit to the right from the known point (0,4), and three units up: this gives the second point (1, 7).
Mark both points, and draw a straight line that goes through both points.
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
Their graphs are.
(2, -1)
3x+56 = 2x+4 3x-2x = 4-56 x = -52
x=6