The lines are parallel.
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
3x + 2 = 3x + 6 This is not possible.
y=2/(3x) + 2 isn't linear so nonthing can be parallel to it as "parallel" can only apply to lines.
(2, -1)
The lines are parallel.
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
y=-2/3x with any y-intercept except -2.
3x + 2 = 3x + 6 This is not possible.
y=2/(3x) + 2 isn't linear so nonthing can be parallel to it as "parallel" can only apply to lines.
(2, -1)
We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
3x + 2 = 0 3x = -2 x = -2/3
4x plus 7 plus 3x equals 19 plus xx = 2
3x + 2 = -10 3x = -12 x = -4
x = 7 and 2/3
3x + 2 = Y