This integral is a bit complicated to try and type here, so I've included a link to a better representation of it below, under "related links". Also, I assume you do not mean to include the "plus 2" in the square root, as the integral becomes considerably more complicated then.
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square root of 12 = sq rt of (4 x3) = 2 x sq rt 3
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
Square root is the same as raise to the 1/2 power, so multiply the exponents {(ab)c = abc}, so sqrt(x^3) = (x3)1/2 = x3/2
Integral of x3/2dx using power rule = (5/2)x5/2 2.5 times the square root of x to the fith.
If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.