Q: How do you integrate square root of x3 plus 2?

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square root of 12 = sq rt of (4 x3) = 2 x sq rt 3

If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator

Square root is the same as raise to the 1/2 power, so multiply the exponents {(ab)c = abc}, so sqrt(x^3) = (x3)1/2 = x3/2

If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.

Integral of x3/2dx using power rule = (5/2)x5/2 2.5 times the square root of x to the fith.

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The square root of x3 is x3/2 or x1.5. Either way it means sqrt(x3).

x3.

sqrt(x3 + x2) = x*sqrt(x+1) and that cannot be simplified further.

square root of 12 = sq rt of (4 x3) = 2 x sq rt 3

If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator

x3/x1/2 = x5/2.

Square root is the same as raise to the 1/2 power, so multiply the exponents {(ab)c = abc}, so sqrt(x^3) = (x3)1/2 = x3/2

It is a polynomial if the square root is in a coefficient but not if it is applied to the variable. A polynomial can have only integer powers of the variable. Thus: sqrt(2)*x3 + 4*x + 3 is a polynomial expression but 2*x3 + 4*sqrt(x) + 3 is not.

If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.

Integral of x3/2dx using power rule = (5/2)x5/2 2.5 times the square root of x to the fith.

2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7

x is.