2x3 - 7 + 5x - x3 + 3x - x3
= 8x - 7
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It is the number (WITH its sign) that comes before the x3 and so it is -2.
use two phase method s.t x1+x2+x3>=3 -x1+2x2>=2 -x1+5x2+x3<=4 x1,x2,x3>=0
The variable term, X^3, is a third order polynomial term and will render three solutions, though one of those may be zero.
y2=x3+3x2
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)