That depends what those nine numbers are. If the numbers are 992, 1, 1, 1, 1, 1, 1, 1, and 1, then it is easy.
If the numbers are all 9s, then it can be written 999 + (999 / 999) = 1000.
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There are 1000 - 9 = 991 of them.
It is: 0.009
291+678+35-4=1000
Should be 1000. (10x10x10)
It is: (IX) which means 1000*9 = 9000
365+735
111 numbers between 5 and 1000 are divisible by 9
3600 * * * * * 9000: from 1000 to 9999 (inclusive).
There are 1000 - 9 = 991 of them.
They are: 9/1000 itself and its equivalent fractions such as 18/2000
999 + 9/9 = 1000
It is: 0.009
300
The first number in this range divisible by 9 is 9 itself...9 = 1 x 9 The last number in the range is 999 = 111 x 9 So there are 111 numbers between 1 and 1000 that are divisible by 9.
291+678+35-4=1000
None of the numbers you listed are evenly divisible by 1000.
Should be 1000. (10x10x10)