There are 1000 - 9 = 991 of them.
It is: 0.009
291+678+35-4=1000
Should be 1000. (10x10x10)
It is: (IX) which means 1000*9 = 9000
365+735
111 numbers between 5 and 1000 are divisible by 9
3600 * * * * * 9000: from 1000 to 9999 (inclusive).
There are 1000 - 9 = 991 of them.
They are: 9/1000 itself and its equivalent fractions such as 18/2000
999 + 9/9 = 1000
It is: 0.009
300
The first number in this range divisible by 9 is 9 itself...9 = 1 x 9 The last number in the range is 999 = 111 x 9 So there are 111 numbers between 1 and 1000 that are divisible by 9.
291+678+35-4=1000
None of the numbers you listed are evenly divisible by 1000.
Should be 1000. (10x10x10)