Q: How do you make 15 using 2 0 1 0?

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Simple: 1*1*1*1*1*15 = 15

One way is: 1+15+8 = 10

you can make them all using 1, 1-1=0 1=1 1+1=2 1+1+1=3 etc.

The system of numbering using only 0 and 1 is called binary. In decimal moving right to left each column is 10 times greater than the last. So 1345 = 1000+300+40+5 In binary moving right to left each column is twice as large. Below you will see some examples. 8 4 2 1 0 0 0 1 = 1 0 0 1 0 = 2 0 0 1 1 = 3 0 1 0 0 = 4 0 1 0 1 = 5 1 0 0 1 = 9 1 1 1 1 = 15

0!=1 =(0! + 0! + 0! + 0! + 0!)! =(1 + 1 + 1 + 1 + 1)! =(5)! =120.

Related questions

1:15 as 6:45 + 6:00 = 12:45 then add 0:15 to make 1:00 then the other 0:15 to make 1:15 as half hour = 0:30 = 0:15 + 0:15

Simple: 1*1*1*1*1*15 = 15

four

X2 - 16X + 15 = 0 (X - 1)(X - 15) = 0 So X -1 = 0 or X - 15 = 0 ie X = 1 or X = 15

One way is: 1+15+8 = 10

you can make them all using 1, 1-1=0 1=1 1+1=2 1+1+1=3 etc.

25 cents = 0 = $0.00 10 cents = 3 = $0.30 5 cents = 1 = $0.05 1 cent = 15 = $0.15 total coins = 19 = $0.50

There are 12 ways to make change for a 50 dollar bill using 5, 10's and 20's. $20's $10's $5's 2 1 0 2 0 2 1 3 0 1 2 2 1 1 4 1 0 6 0 5 0 0 4 2 0 3 4 0 2 6 0 1 8 0 0 10

The system of numbering using only 0 and 1 is called binary. In decimal moving right to left each column is 10 times greater than the last. So 1345 = 1000+300+40+5 In binary moving right to left each column is twice as large. Below you will see some examples. 8 4 2 1 0 0 0 1 = 1 0 0 1 0 = 2 0 0 1 1 = 3 0 1 0 0 = 4 0 1 0 1 = 5 1 0 0 1 = 9 1 1 1 1 = 15

0!=1 =(0! + 0! + 0! + 0! + 0!)! =(1 + 1 + 1 + 1 + 1)! =(5)! =120.

AnswerAnswer: ( 0! + 0! + 0! + 0! + 0! ) ! = 120 Explanation: Here we have used operator called " factorial ". As you know that 0! = 1 so, = ( 0! + 0! + 0! + 0! + 0! ) ! = ( 1 + 1 + 1 + 1 + 1 ) ! = (5 )! = 120 : ( 0! + 0! + 0! + 0! + 0! ) ! = 120 Explanation: Here we have used operator called " factorial ". As you know that 0! = 1 so, = ( 0! + 0! + 0! + 0! + 0! ) ! = ( 1 + 1 + 1 + 1 + 1 ) ! = (5 )! = 120

(x - 3)*(x + 5)*(x - 1) = 0 (x2 - 3x + 5x - 15)*(x - 1) = 0 (x2 + 2x - 15)*(x - 1) = 0 (x3 + 2x2 - 15x - x2 - 2x + 15) = 0 ie x3 + x2 - 17x + 15 = 0