(4x4+4)/4
4 /5
(4 + 4)*4 + 4 + 4 = 42
4/4 + 4 × 4/4
yes by taking out one then u will get 4 like 5-1=4 like that simple as that.....loxl..hehehe..its so funny
4$4=*^5 then ..... from the 5 you do @ 4 ...... finally 4 * 2 making it 21
I am not aware of a solution using the four basic operations of arithmetic, but otherwise: 129 = [(4^4)/sqrt(4)] + sqrt(sqrt(sqrt(sqrt...(sqrt(4))...))) * * * * * * * * * * * * No matter how many times you square root it, it will not equal 1 To the OP. I have spend a lot of time on this one. Just wanting to make sure that the correct number is 129 and you are sure you are using only 4 fours. It would work out great if using 5 fours. If you made a mistake, correct it and I'll check back. In the mean time, I'll continue thinking about a solution for 4 fours and 129.
((4 times 4) plus 4) divided by 4.
I can do it with 3: 4 * 4 + 4 = 1416(base 16) But that's probably not what you are looking for. The closest I can get is with 5 fours: 4 * 4 - (4 + 4) / 4
4 - (4/4 x 4/4) or 4 + 4 - 4 - 4/4
((-4 x -4)-(-4))/-4 (16-(-4))/-4 (16+4)/-4 20/-4 = -5
[(4 times 4)+4] divided by 4