There are six fours in twenty-four.
Once with two remaining
4 × ((4 ÷ 4) + 4)=20
One way to use four fours to make 25 is 4 + 4 + 4 + √4, which equals 25.
4 + 4 + (4/4) = 9
There are six fours in twenty-four.
(4+4)/4 + 4 =6
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
Once with two remaining
4 × ((4 ÷ 4) + 4)=20
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
One way to use four fours to make 25 is 4 + 4 + 4 + √4, which equals 25.
4+4-(4/4)=7
11 = 4/.4 + 4/4
4 + 4 + (4/4) = 9
(4/4)*4!/4 = 6
Yes. Assuming you can use any mathematical formula that only uses four fours, you can take the square root of four (2) plus four (6) plus four over four, which simplifies to 1 over one, which is one, you simply get two plus four plus one, or seven