A solution to the four fours problem for the number 33 is:
33 = (4-.4)/.4+4!
33 + (3/3)
Use two of the 3s to make 33. Then: 33 - 3 = 11 11 + 3 = 14
The numbers that are divisible by 33 are infinite. The first four are: 33, 66, 99, 132 . . .
To arrange 5 three's to equal 100, you can use the following mathematical expression: (3 + 3) x (3 + 3 + 3 + 3) = 6 x 12 = 72. Then, add the remaining three: 72 + 3 + 3 + 3 + 3 + 3 = 100. So, you can arrange 5 three's to equal 100 by using a combination of addition and multiplication.
A square has four sides that are all the same length. If one side is 33-ft then all four sides are 33-ft, and the distance all the way around the square is (33 x 4) = 132 feet.
33 + (3/3)
33 + 3 + 3 = 3333 + 3/3 = 33 + 1 = 34
To make 33 using just four fours, your solution is: (4 - .4) / .4 + 4! To break this down into individual steps, this works out as follows: 4 - .4 = 3.6 / .4 = 9 + 4! = 33. You can also make 33 using three fours. 4! + 4 / 4` The ` sign, similar to a grave accent, turns the number in question into a recurring decimal - in other words, four ninths. Don't forget to apply the rules of BODMAS, whereby you apply the division before you apply the addition in the sum. Therefore: 4 / (4/9) + (4 x 3 x 2 x 1) = 33.
54 = 2*33
Use two of the 3s to make 33. Then: 33 - 3 = 11 11 + 3 = 14
(33 + 3!) / 3 = (33 + 6) / 3 = 39 / 3 = 13.
(33 ÷ 3) + 3 = 14
33, 66, 99, 132
There are four: 1, 3, 11 and 33
No, is not divisible by 33. It is divisible by 32 so it can't be by 33.
The four middle lines of latitude are the Tropic of Cancer, the Tropic of Capricorn, the International Date Line and the Prime Meridian. They are found at 330 33' 33" N, 660 33' 33" N, 630 33' 33" S, and 330 33' 33" S.
Four of them.