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Using pennies, nickels, and dimes: 85 pennies 1 nickel 1 dime Total = 87 coins.
3 coins- 1 half dollar, 1 quarter, and 1 dime. 4 coins- 3 quarters and 1 dime.
a dime, a quarter and a fifty-cent piece.
A set of half dollar quarter and dime is worth 50+25+10 = 85 cents. So, with an equal number of these coins the sum can only be a multiple of 85 cents. 15 dollars is not a multiple so cannot be so changed.
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To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)
1x25,6x10=85
3 quarters & 2 nickels
I don't think that this can be done using current US coins. In Canada, however, there are at least three combinations: -- 80 cents, 17 dimes, 2 quarters and a two-dollar coin -- 85 cents, 9 dimes, 5 quarters and a two-dollar coin -- 90 cents 1 dime, 8 quarters and a two dollar coin
Using pennies, nickels, and dimes: 85 pennies 1 nickel 1 dime Total = 87 coins.
Two quarters, one dime, four nickels, five pennies
3 coins- 1 half dollar, 1 quarter, and 1 dime. 4 coins- 3 quarters and 1 dime.
85 cents
85 cents