if you want to use 8*3 encoder than you must the design the circuit according to variable and with the help of k-map and you can not construct the circuit of 8*3 encoder using 7432 (which is or gate ic) only. you need AND gate 7408 and may be NOT 7404 gate according to design.
karthika only know answer to this question
Points: (8, 3) and (8, 7) Slope: 0 The line is a straight vertical line parallel to the y axis
3 and 8
6x+3y = 8 3y = -6x+8 y = -3x+8/3 The slope of the line is -3
Tor futki
if you want to use 8*3 encoder than you must the design the circuit according to variable and with the help of k-map and you can not construct the circuit of 8*3 encoder using 7432 (which is or gate ic) only. you need AND gate 7408 and may be NOT 7404 gate according to design.
karthika only know answer to this question
28 = 256, so an 8 bit encoder would have a resolution of one part in 256, or 0.39%.
Decoder is a circuit which have n inputs and 2^n outputs.I think you want to say encoder which have 2^n input and n output lines. So your required chip is 8(2^3)X3 encoder which does not exist.
Points: (8, 3) and (8, 7) Slope: 0 The line is a straight vertical line parallel to the y axis
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
Line DE is 15 Line PQ is 5 Line DF is 21 Line PR is x 15/3 = 5 21/3 = 7 Line PR is 7 CHECK TO MAKE SURE IT MATCHES (stay safe)
3 and 8
6x+3y = 8 3y = -6x+8 y = -3x+8/3 The slope of the line is -3
Is -3 greater or less then +8?-3 is less than +8 because, on the number line -3 is before 0, and on the number line +8 is after 0. ( All numbers after the 0 on the number line have an invisible + sign in front of them. They are not necessary to add, and most people don't.)
An encoder is a combinational circuit that converts a signal on exactly one input into its corresponding binary number.The maximum number of inputs is directly related to the number of outputs. Anencoder with n outputs supports 2^n inputs. When n = 2, there are 2^2 = 4 inputsthat can be encoded. When n = 3, there are 2^3 = 8 inputs that can be encoded.