This depends on the volume of the 40 percent solution you have. The question can be rewritten as:
40%a/(a+b) = 3% where a is the volume of the 40% solution, and b is the volume of water we need to add. Multiply both sides by (a+b) to get:
40%a = 3%a + 3%b
Subtract 3%a from both sides to get
37%a = 3%b
Divide by 3% to get:
12.3333...a = b
Thus whatever the current volume is, you need to add 12.33333 times that volume in water in order to get a 3% solution.
40 increased by 3 percent = 41.2 = 40 + (3% * 40) = 40 + (0.03 * 40) = 40 + 1.2 = 41.2
3% of 40 = 0.03 x 40 = 1.2
2.3 percent glucose solution and .3 percent sodium solution
50 gallons @ 3% must be added.
It is 3.'3'% recurring '3'
3 percent of 40 = 1.23% of 40= 3% * 40= 0.03 * 40= 1.2
40 increased by 3 percent = 41.2 = 40 + (3% * 40) = 40 + (0.03 * 40) = 40 + 1.2 = 41.2
A 3 percent solution is 1.5 times as strong as a 2 percent solution.
3 over 40 as a percent = 7.5%= 3/40 * 100%= 0.075 * 100%= 7.5%
Let there be x litres of 50% solution and y% of 20 % solution, then you have two equations by considering the amount of alcohol and the total amount of liquid:50% x + 20% y = 40% of 3 litresx + y = 3 litresThese are two simultaneous equations involving 2 unknowns which can be solved:Double {1} and subtract from {2} to give:x - x + y - 40%y = 3 - 80% of 3→ 60% y = 20% of 3→ y = 20%/60% of 3 = 1/3 of 3 = 1Substitute for y in {2} to get:x + 1 = 3x = 2Therefore you need 2 litres of 50% solution and 1 litre of 20% solution.
Expressed as a percentage, 3/40 x 100 = 7.5 percent.
To make a 10 vol peroxide solution from a 40 vol peroxide solution, you would need to dilute the 40 vol peroxide solution by adding three parts water for every part of the 40 vol peroxide solution. For example, mix 1 part 40 vol peroxide with 3 parts water to achieve a 10 vol peroxide solution.
if you mean 75% of 40: 75% equals 3/4 so 3/4 of 40 is 30; or 30/40
3% of 40 = 0.03 x 40 = 1.2
2.3 percent glucose solution and .3 percent sodium solution
50 gallons @ 3% must be added.
7.5%