by breaking your head
3x3 magic square 25 total
Yes. Simply take a square with one and add the same number to each one of the numbers in it.
Start with a magic square which includes the number 3. Then either: Add 3 to each number, or Multiply each number by any integer other than 3.
Ten.
Think! What if the magic square had an even number of cells. There's your answer.
by flipping fraction and square rootin.
3x3 magic square 25 total
its impossible because in a 4 by 4 magic square u need 16 numbers u cant do it with just 0-9
Yes. Simply take a square with one and add the same number to each one of the numbers in it.
Start with a magic square which includes the number 3. Then either: Add 3 to each number, or Multiply each number by any integer other than 3.
The constant is 34.
Ten.
Just take any magic square, and multiply every number by 5. Here you will get another magic square with all numbers multiples of 5.
Think! What if the magic square had an even number of cells. There's your answer.
In an 8x8 magic square, the sum of each row, column, and diagonal is the same, known as the magic constant. For an n x n magic square, the magic constant can be calculated using the formula ( M = \frac{n(n^2 + 1)}{2} ). For an 8x8 magic square, this gives ( M = \frac{8(64 + 1)}{2} = 260 ). Therefore, the sum in the 1st row of an 8x8 magic square is 260.
A 1-9 magic square must add to 15.
Albrecht Dürer drew a 'magic square' in his engraving 'Melencolia I'. But I do not think he invented it.