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finding the equation of a line of (-1,2) and (1,2):

formula:

y=mx+b

m = slope

b = y intercept

first find m: m=(y2-y1)/(x2-x1)

so, m=(2-2)/ (1- -1)

m=0

since you now know m you can plug that in to the formula:

y=0x+b

to get b:

plug in the coordinates (either (-1,2) or (1,2)), it comes out the same

(-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2

(1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2

you now know that m=0 and b=2, now plug that back in the equation to get:

y=mx+b

y=0x+2

y+2

It's confusing, but it works!

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14y ago
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15y ago

It depends on what type of equation you are graphing. It is also important to know what form the function is in, whether it is standard or intercept, etc.

y=mx+b
The y-intercept is b, and mark the next point depending on the slope.

y=ax2+bx+c
Either factor it into (x-h)(x-k) or use the quadratic formula.

y=a(x-h)2+k
Point (h,k) will be the vertex and line of symmetry

Those are a few of many ways of graphing an equation. You may also randomly plug in easy x values of a y.
Or you can use a graphing calculator if your trying for a D-

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