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finding the equation of a line of (-1,2) and (1,2):

formula:

y=mx+b

m = slope

b = y intercept

first find m: m=(y2-y1)/(x2-x1)

so, m=(2-2)/ (1- -1)

m=0

since you now know m you can plug that in to the formula:

y=0x+b

to get b:

plug in the coordinates (either (-1,2) or (1,2)), it comes out the same

(-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2

(1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2

you now know that m=0 and b=2, now plug that back in the equation to get:

y=mx+b

y=0x+2

y+2

It's confusing, but it works!

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