Perimeter and area are not sufficient to determine the shape of a figure.
a rectangle
Yes.
The simplest shape is a 6ft*3 ft rectangle.
No. Consider two rectangles: 1 x 10 and 4 x 5 The 1 x 10 has a perimeter of 22 and an area of 10 The 4 x 5 has a perimeter of 18 and an area of 20 Smaller perimeter, twice the area.
Yes if you
Perimeter and area are not sufficient to determine the shape of a figure.
Actually it is possible.
a rectangle
It depends. What shape is it? And is it equilateral or not?
Yes.
Yes. Use excel with 18 boxes. Offsetting the boxes will get you the right answer.
The simplest shape is a 6ft*3 ft rectangle.
No, because you would need a calculation os 3 to make a calculation of 6, and 18 and 20 aren't friendly to one another!
No. Consider two rectangles: 1 x 10 and 4 x 5 The 1 x 10 has a perimeter of 22 and an area of 10 The 4 x 5 has a perimeter of 18 and an area of 20 Smaller perimeter, twice the area.
The perimeter and area of a shape do not provide sufficient information. With a given perimeter, the largest area that you can enclose is a circle, but you can then flatten the circle to reduce its area. Similarly, in terms a of quadrilaterals, a square has the largest area, but it can be flexed into a rhombus whose area can be made as small as you like. All that can be said is that there is no shape with a perimeter of 12 units whose area is 12 square units.
Surface area is the perimeter (amount of space around a shape) around a shape. For example: I have a rectangle So: 3+3=6 9+9=18 18+18=36cm2