If the 2 triangles are right triangles, which are congruent to slicing the rectangle on the diagonal, then arrange one on top of the rectangle, and the other to the side, so that the two hypotenuses are in line with each other. This will make a bigger right triangle, which is similar to the smaller right triangles - each side is double of the smaller triangles.
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By cutting off two of its corners which will leave you with 2 triangles and 1 pentagon.
You will have to use a formula, but this can easily be derived for the special case of a right triangle. If you divide a rectangle by a diagonal, you divide it into two congruent triangles, therefore, the triangle has half the area of the rectangle, that is, 1/2 times base times height.
You can make 6
To make a triangle fold it diagonally vertex to vertex To make a rectangle fold it side to side To make an irregular pentagon fold over one corner without touching the opposite corner
You get two congruent right triangles when you divide a rectangle diagonally. (This is one way to show that the area of each of those triangles is 1/2*base*height. Rectangle area = (4 in)(8 in) = 32 in2. Triangle area = (1/2)(4 in)(8 in) = 16 in2.)