If the 2 triangles are right triangles, which are congruent to slicing the rectangle on the diagonal, then arrange one on top of the rectangle, and the other to the side, so that the two hypotenuses are in line with each other. This will make a bigger right triangle, which is similar to the smaller right triangles - each side is double of the smaller triangles.
By cutting off two of its corners which will leave you with 2 triangles and 1 pentagon.
You will have to use a formula, but this can easily be derived for the special case of a right triangle. If you divide a rectangle by a diagonal, you divide it into two congruent triangles, therefore, the triangle has half the area of the rectangle, that is, 1/2 times base times height.
You can make 6
To make a triangle fold it diagonally vertex to vertex To make a rectangle fold it side to side To make an irregular pentagon fold over one corner without touching the opposite corner
You get two congruent right triangles when you divide a rectangle diagonally. (This is one way to show that the area of each of those triangles is 1/2*base*height. Rectangle area = (4 in)(8 in) = 32 in2. Triangle area = (1/2)(4 in)(8 in) = 16 in2.)
two right triangles = full rectangle That is - if you multiply height times base of a triangle, the area will be 1/2 of a rectangle having the same height, and a width the same as the triangle base.
Picture a square. now make a line connecting the two diagonal points. If bh is the volume of the rectangle, then we only have half a rectangle for each right triangle giving 1/2 *bh or bh/2. For any other traingle put the base parallel to the ground. Make a perpendicular line to the ground then you have two parts of a triangle divided at a vertex. Each of the these parts has a right angle. Make a second triangle of the same size and if you turn it into the two triangle fromt he first triangle and cut it apart, you can manipulate it to make a rectangle. The two triangles are a rectangle which is bh. divide by two to get one triangle so 1/2*bh or bh/2
there are 27 triangles in a triangle
a BIG HUGE triangle i am in the 2ndgrade and i am 8 i am in glenarnden woods elem. in pgcps
2 small triangles 1 med. triangle 2 large triangles 1 parallelogram and a square
By cutting off two of its corners which will leave you with 2 triangles and 1 pentagon.
You will have to use a formula, but this can easily be derived for the special case of a right triangle. If you divide a rectangle by a diagonal, you divide it into two congruent triangles, therefore, the triangle has half the area of the rectangle, that is, 1/2 times base times height.
You can make 6
To make a triangle fold it diagonally vertex to vertex To make a rectangle fold it side to side To make an irregular pentagon fold over one corner without touching the opposite corner
1
You get two congruent right triangles when you divide a rectangle diagonally. (This is one way to show that the area of each of those triangles is 1/2*base*height. Rectangle area = (4 in)(8 in) = 32 in2. Triangle area = (1/2)(4 in)(8 in) = 16 in2.)
1 triangle 1 pentagon and 2 trapezoids