The expression in the question does not define an area.
g(3y) can be any function: it is not defined by the question.
5y+14+y = 3y-7 5y+y-3y = -7-14 3y = -21 y = -7
2x - 3y = 62x = 3y + 63y = 2x - 6y = (2x - 6)/3y = (2/3)x - 2
3y = 4x + 9 -4x + 3y = 9 is the standard form
x = 3y x - 3y = 3y - 3y x - 3y = 3y - 3y x - 3y = 0
3y +3y = 6y
3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y
The equation for 3y + 3y = -1 is 3y + 3y = -1.
-3y+6 = -3(y-2) -3y-6=-3(y+2) It is not what ever that is right there, i can tell you THAT for sure! An identity used to simplify an equation using parentheses: 4(x)+4(y) = 4x+4y
(3y2 - 3y)/(y - 1) = 3y(y - 1)/(y - 1) = 3y
if you wish to multiply 3y-2y by 3y-y the answer is 2y^2
3(2x + 3y)(2x - 3y)
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3
4xy²(3y-x)-2x²(x-3y)²=4xy²(x-3y)-2x²(x-3y)²=(x-3y)[4xy²-2x²(x-3y)²]=(x-3y)(4xy²-2x³+6x²y)=(x-3y)(-2x³+6x²y+4xy²)=-2x(x-3y)(x²-3xy-2y²)= -2x(x-3y)(x-y)(x-2y)
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
2x/3y