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# How do you factorize 4xy²(3y-x)-2x²(x-3y)² to get -2x(x-3y)(x-y)(x-2y)?

Updated: 4/28/2022

Wiki User

8y ago

4xyÂ²(3y-x)-2xÂ²(x-3y)Â²=4xyÂ²(x-3y)-2xÂ²(x-3y)Â²=(x-3y)[4xyÂ²-2xÂ²(x-3y)Â²]=(x-3y)(4xyÂ²-2xÂ³+6xÂ²y)=(x-3y)(-2xÂ³+6xÂ²y+4xyÂ²)=-2x(x-3y)(xÂ²-3xy-2yÂ²)= -2x(x-3y)(x-y)(x-2y)

Wiki User

8y ago

Anonymous

Lvl 1
4y ago

4xy² -2x²

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Q: How do you factorize 4xy²(3y-x)-2x²(x-3y)² to get -2x(x-3y)(x-y)(x-2y)?
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