You cannot make four triangles our of a quadrilateral by ONE line through it. One line can give you at most two triangles.
Two lines, each running from one vertex of the quadrilateral to the opposite vertex, will give 4 triangles.
Put the triangles in a line alternately pointing up and down.
A straight line can intersect the side of a convex quadrilateral in at most two points and so divided it into at most two segments. A concave quadrilateral (an arrowhed or chevron) can be divided into three if the line touches the reflex vertex and cuts off the two "barbs" of the arrowhead. But 4 triangles is not possible.
Not necessarly. If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
Four line segments can always form a quadrilateral, as long as none of them is longer than the sum of the lengths of the other three,
50% because a trapezoid is made from 2 triangles
Put the triangles in a line alternately pointing up and down.
You can always find opposite corners that can be connected with a line which divides the quadrilateral into two trilaterals.
A quadrilateral is a shape with four sides.
A quadrilateral is any plane figure bounded by four straight lines. If a line is drawn from one corner to the opposite corner of a quadrilateral then it is divides the quadrilateral into two triangles. As the sum of the angles of a triangle is 180° then the sum of the internal angles of a quadrilateral total 360°. Special forms of a quadrilateral are :- Parallelogram, Rhombus. Rectangle, Square, Trapezoid / Trapezium and Kite.
If you accept that the sum of the angles in a triangle is 180 degrees, then picture this. A quadrilateral shape is two triangles. If you draw a line between one pair of opposite corners in quadrilateral shape, you have two triangles that share a common side. The sum of the angles in the quadrilateral must equal the sum of the angles in the two triangles. 2 x 180 = 360
A straight line can intersect the side of a convex quadrilateral in at most two points and so divided it into at most two segments. A concave quadrilateral (an arrowhed or chevron) can be divided into three if the line touches the reflex vertex and cuts off the two "barbs" of the arrowhead. But 4 triangles is not possible.
Not necessarly. If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
Four line segments can always form a quadrilateral, as long as none of them is longer than the sum of the lengths of the other three,
50% because a trapezoid is made from 2 triangles
Are you testing us? *gets paper* 9 if you dont count triangles with a line going through it 17 if you count triangles with more than one line going through it e.g all possible triangles visible
Bullets Triangles Horizontal Triangles Plus Sign Circle with line through it Bull's-Eye
YES, a quadrilateral does have a line of symmetry.