84
^
21 4
^ ^
7 3 2 2 84
^
42 2
^
21 2
^
7 3
Can somerone please explain how to do a factor fireworks problem? I am completely lost on how they work. I need two different factor fireworks of 64.
There are Two factor trees for 20
(15,2)(10,3)
Multiply 9 by two different numbers (9 x a, and 9 x b). Make the two numbers, a and b, relatively prime. For example, one of them can be 1; or just choose two different prime numbers.
14 is a factor of 532.
Can somerone please explain how to do a factor fireworks problem? I am completely lost on how they work. I need two different factor fireworks of 64.
2,2,2,2,2,2 4,2,2,2,2 8,2,2,2 16,2,2 32,2 64 2,2,2,2,2,2 2,2,2,4,2 2,2,2,8 4,2,8 8,8 64
2,2,2,2,2,2 4,2,2,2,2 8,2,2,2 16,2,2 32,2 64 2,2,2,2,2,2 2,2,2,4,2 2,2,2,8 4,2,8 8,8 64
The two-factor fireworks for the number 84 are the pairs of factors that when multiplied together equal 84. These pairs are (1, 84), (2, 42), (3, 28), (4, 21), (6, 14), and (7, 12). Each pair represents a unique combination of factors contributing to the product of 84.
Bigger numbers make bigger factor trees, and of course there are prime numbers which cant be factored at all
The factor of two plus two is four.
"Fireworks" has two syllables: fire-works.
There are Two factor trees for 20
44,122,211,4
they are two different things
Any two.
"Fireworks" is one word.