2,2,2,2,2,2
4,2,2,2,2
8,2,2,2
16,2,2
32,2
64
2,2,2,2,2,2
2,2,2,4,2
2,2,2,8
4,2,8
8,8
64
Yes, the greatest common factor of two different prime numbers is always 1
100 50,2 25,2,2 5,5,2,2 100 4,25 4,5,5 2,2,5,5
Yes, that is correct.
14 can never be the least common factor of two numbers. The least common factor of any two numbers is 1.
The two numbers that don’t end in zero and have a factor of 10,000,000 are 1 and 10,000,000 itself. Since 10,000,000 contains the factor of 10, which contributes two zeros, 1 does not end in zero, while 10,000,000 is typically considered when factoring. However, as a product of prime factors, 10,000,000 can be expressed in different combinations that do not include the factor of 10, leading us to consider the number 1.
Can somerone please explain how to do a factor fireworks problem? I am completely lost on how they work. I need two different factor fireworks of 64.
2,2,2,2,2,2 4,2,2,2,2 8,2,2,2 16,2,2 32,2 64 2,2,2,2,2,2 2,2,2,4,2 2,2,2,8 4,2,8 8,8 64
84 ^ 21 4 ^ ^ 7 3 2 2 84 ^ 42 2 ^ 21 2 ^ 7 3
The two-factor fireworks for the number 84 are the pairs of factors that when multiplied together equal 84. These pairs are (1, 84), (2, 42), (3, 28), (4, 21), (6, 14), and (7, 12). Each pair represents a unique combination of factors contributing to the product of 84.
Bigger numbers make bigger factor trees, and of course there are prime numbers which cant be factored at all
The factor of two plus two is four.
"Fireworks" has two syllables: fire-works.
There are Two factor trees for 20
44,122,211,4
they are two different things
Any two.
"Fireworks" is one word.