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How do you prove that the diagonals of a square are equal and perpendicular to each other?
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Are the diagonals of a square equal and perpindicular besides bisecting each other?
Yes, the diagonals of a square are congruent (equal in length) and are perpendicular.
Are a trapeziums diagonals perpendicular?
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
What is the name of the quadrilateral that are perpendicular and bisect each other?
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Are the diagonals perpendicular?
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
Are the diagonals of a square perpendicular bisectors to each other?
Yes
Are the diagonals of a square equal and perpindicular besides bisecting each other?
Yes, the diagonals of a square are congruent (equal in length) and are perpendicular.
Are the diagonals of a rhombus perpendicular and bisect each other?
Yes, they are perpendicular and intersect at their midpoints. The difference between diagonals in a rhombus as opposed to a rectangle or square is that the diagonals are not of equal length.
Are a trapeziums diagonals perpendicular?
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
What is the name of the quadrilateral that are perpendicular and bisect each other?
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Are the diagonals perpendicular?
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
Why are the diagonals of a square perpendicular bisectors of each other?
You could prove this by congruent triangles, but here are two simpler arguments: --------------- Since a square is a rhombus, and the diagonals of a rhombus are perpendicular bisectors of each other, then the diagonals of a square must be perpendicular bisectors of each other -------------------- A square has four-fold rotational symmetry - as you rotate it around the point where the diagonals cross, there are four positions in which it looks the same. This means that the four angles at the centre must be equal. They will each measure 360/4 = 90 degrees, so the diagonals are perpendicular. Also. the four segments joining the centre to a vertex are all equal, so the diagonals bisect each other.
What shape is a parallelogram with all angles equal to 90 degrees and it's diagonals are perpendicular on each other?
A square.
Do the diagonals on a square perpendicular to each other?
Yes they do.
Are the diagonals of a square perpendicular?
Yes, to each other.
The diagonals of a square are perpendicular bisectors of each other?
Yes
What type of quadrilateral has diagonals the are perpendicular to each other?
A square has.
Are the diagonals of a square perpendicular bisectors to each other?
Yes
