To prove that the diagonals of a square are equal and perpendicular, start by noting that a square has four equal sides and four right angles. By using the distance formula, calculate the lengths of the diagonals; since both diagonals connect opposite vertices, they will have the same length, confirming they are equal. To show they are perpendicular, observe that the slopes of the diagonals are negative reciprocals of each other, as they intersect at right angles, demonstrating that the diagonals are perpendicular. Thus, the properties of the square ensure that both conditions are satisfied.
Yes, the diagonals of a square are congruent (equal in length) and are perpendicular.
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
Yes, a square is a special type of parallelogram. By definition, a parallelogram has opposite sides that are equal and parallel, and in a square, all four sides are equal. Additionally, a square has diagonals that are both congruent (equal in length) and perpendicular (intersecting at right angles), which further distinguishes it from other types of parallelograms.
Yes, the diagonals of a square are congruent (equal in length) and are perpendicular.
Yes, they are perpendicular and intersect at their midpoints. The difference between diagonals in a rhombus as opposed to a rectangle or square is that the diagonals are not of equal length.
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
You could prove this by congruent triangles, but here are two simpler arguments: --------------- Since a square is a rhombus, and the diagonals of a rhombus are perpendicular bisectors of each other, then the diagonals of a square must be perpendicular bisectors of each other -------------------- A square has four-fold rotational symmetry - as you rotate it around the point where the diagonals cross, there are four positions in which it looks the same. This means that the four angles at the centre must be equal. They will each measure 360/4 = 90 degrees, so the diagonals are perpendicular. Also. the four segments joining the centre to a vertex are all equal, so the diagonals bisect each other.
Yes they do.
A square.
Yes, a square is a special type of parallelogram. By definition, a parallelogram has opposite sides that are equal and parallel, and in a square, all four sides are equal. Additionally, a square has diagonals that are both congruent (equal in length) and perpendicular (intersecting at right angles), which further distinguishes it from other types of parallelograms.
Diagonals are perpendicular to each other in several types of quadrilaterals, including rhombuses, squares, and kites. In a rhombus, the diagonals bisect each other at right angles, while in a square, they are both perpendicular and equal in length. Kites also have diagonals that intersect at right angles, though one diagonal is usually longer than the other.
Yes, to each other.
Yes