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Slowly add drip, by drip.....from your saltwater aqarium . I use an air tube tied in a knot so it drips about 1 drip per secound. Drip directly from your aquarim into atleast a 2 gallon contaier . Put your fish and the water its in in your bucket. Then let drip on him until your contaier is full. When full pour half the water back into your aqarium. Simply let it fill up again . By the time its full your fish should be fully accimated
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What is the difference in weight between a gallon of salt water and a gallon of fresh water?
salt water has more mass because of the added salt so salt is heavier :)
What percentage of the worldswater is salt water?
97% of the worlds water is Salt water. 71% of the world is Covered by Saltwater.
What are the probable sources of salt in the atmosphere?
the ocean. water from the ocean evaporates into the air, ocean water has salt in it.
What is the weight of salt water of one cubic meter?
what is the weight of salt water of one cubic meter
How many milligrams of salt must be added to 18 milligrams of a 20 percent salt solution to obtain a 35 percent salt solution?
this question is not hard to answer, but it does require that one make some assumptions. The simplest answer assumes that the 20% salt solution refers to per cent by mass. Thus: a 20% salt solution is one which contains 20 mg salt for every 100 mg solution where the solution consists of a mixture of 20 mg salt plus 80 mg water. A 35% salt solution would contain 35 mg salt for every 65 mg water. Now, assuming that all the water in 18 mg of a 20% salt solution remains in the final solution we see that 18 mg salt solution x 20 mg salt/100 mg salt solution gives 3.6 mg of salt; thus, there are 18 mg total solution - 3.6 mg salt = 14.4 mg water. So the final salt solution must be one that contains 14.4 mg water and enough salt to make it 35% salt by mass. Mathematically, this is written as Z mg salt/(Z mg + 14.4 mg water) = 35/100 This gives Z = 0.35*(Z + 14.4) or Z = 0.35*Z + 0.35*14.4 which is same as Z = 0.35*Z + 5.04 and 0.65*Z = 5.04 so Z = 5.04/0.65 = 7.75 mg total salt needed. We started with 3.6 mg salt, so we must add 7.75 -3.6 = 4.15 mg salt Check: 7.75 mg salt/(7.75 mg salt + 14.4 mg water) = 0.35 or 35% There you go! --assuming that much salt dissolves that amount of water!
