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What notes are in the scale of B minor?
B Natural minor: B, C#, D, E, F#, G, A, B B Harmonic minor (raise the 7th) B, C#, D, E, F#, G, A#, B B melodic minor (traditional) (Raise the 6th and 7th going up, drop on way down) B, C#, D, E, F#, G#, A#, B (Ascending) B, C#, D, E, F#, G, A, B (Descending) B melodic minor (Jazz) (raise the 6th and 7th regardless if going up or down. B, C#, D, E, F#, G#, A#, B
Maria keeps her four stuffed bears lined up on a shelf over her bed how many arrangements of the bears are possible?
The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a
C program to print all combinations of a 4-digit number?
#include<stdio.h> int main() { int a,b,c,d; for(a=1; a<5; a++) { for(b=1; b<5; b++) { for(c=1; c<5; c++) { for(d=1; d<5; d++) { if(!(a==b a==c a==d b==c b==d c==d)) printf("dd\n",a,b,c,d); } } } } return 0; }
How can you write a c program to find maximum element in row and minimum element in column of a matrix?
#include <stdio.h> main() { int m, n, c, d, A[10][10],temp=0; printf("\nEnter the number of rows and columns for matrix A:\n"); scanf("%d%d", &m, &n); printf("\nEnter the elements of matrix A:\n"); for ( c = 0 ; c < m ; c++ ) for ( d = 0 ; d < n ; d++ ) scanf("%d", &A[c][d]); printf("\nMatrix entered is:\n"); for ( c = 0 ; c < m ; c++ ) { for ( d = 0 ; d < n ; d++ ) printf("%d\t", A[c][d]); printf("\n"); } printf("\n\nMaximum element of each row is:\n"); for(c=0;c<m;c++) { for(d=0;d<n;d++) { if(A[c][d]>temp) temp=A[c][d]; } printf("\n\t\tRow %d: %d",c+1,temp); temp=0; } temp=A[0][0]; printf("\n\nMinimum element of each coloumn is:\n"); for(c=0;c<n;c++) { for(d=0;d<m;d++) { if(A[d][c]<temp) temp=A[d][c]; } printf("\n\t\tColoumn %d: %d",c+1,temp); temp=A[d][c] ; } return 0; }
A c plus plus program illustrating rational number?
int a=2, b=3, c=4, d=5; printf ("%d/%d + %d/%d = %d/%d\n", a, b, c, d, a*d+b*c, b*d);
