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An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator.

If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).

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Q: How do you rationalize denominator surds?
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