0.625
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
0.4
3.5714
Multiplicative inverse is the number that, when multiplied, results in 1, usually 1/# 1/sqrt7 is the inverse, so just rationalize the denominator sqrt7/7 = square root of 7 divided by 7
6
0.625
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).
0.4
3.5714
1.5
Multiplicative inverse is the number that, when multiplied, results in 1, usually 1/# 1/sqrt7 is the inverse, so just rationalize the denominator sqrt7/7 = square root of 7 divided by 7
An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator. If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).
Yes, the expression 2 divided by 2 square root 3 can be simplified. To simplify this expression, we need to rationalize the denominator. Multiplying both the numerator and the denominator by the conjugate of the denominator (2 square root 3), we get (2 * 2 square root 3) / (2 * 2 square root 3 * 2 square root 3). This simplifies to 4 square root 3 / 12, which further simplifies to square root 3 / 3.
No, you can also use conjugates with more than one radical term. For example, if the denominator is root(2) + root(3), you can use the conjugate root(2) - root(3) to rationalize the denominator.