6 + 7 = 13 13 can't fit into the ones place. Regroup 13 ones into one ten and three ones. Leave the three ones in the ones place and carry the one ten over to the tens place.
851 dollars. 7 hundreds (7*100) =700 14 tens (14*10) = 140 11 ones (11*1) = 11 700+140+11= 851
7 tens and 4 ones 5 thousandths = 74.005
90 + 7 is not and has never been equal to 70 + 9
The first (left most) digit is the number of tens and the other is the number of ones. So 57 = 5 tens plus 7 ones = 50 + 7 = 57
Well, isn't that just a happy little math problem! If you have 7 tens, that's like having 7 groups of 10. And in each group of 10, there are 10 ones. So, if you have 7 tens, you have 70 ones. Just imagine all those little ones happily lining up to join the big group of tens!
26
6 + 7 = 13 13 can't fit into the ones place. Regroup 13 ones into one ten and three ones. Leave the three ones in the ones place and carry the one ten over to the tens place.
7 tens and 20 ones is 7 × 10 + 20 × 1 = 70 + 20 = 90 (ninety).
To find the number represented by 7 tens and 9 ones, you would multiply 7 by 10 (since there are 10 ones in a ten) to get 70, and then add the 9 ones to get the final number. Therefore, 7 tens and 9 ones is equal to 79.
For example, a seven in the tens place would equal to 70 whereas a 7 in the ones place equals 7.
6+6 7+7 10+8 6+4
The number that has 9 tens and 7 fewer ones than tens is 83. This is because 9 tens equal 90, and if we have 7 fewer ones than tens, we subtract 7 from the tens place, giving us 90 - 7 = 83. Therefore, the number with 9 tens and 7 fewer ones than tens is 83.
7 hundreds, 16 tens 4 ones is 7 x 100 + 16 x 10 + 4 x 1 = 700 + 160 + 4 = 864.
35 tens and 7 0nes
17 tens = (10 + 7) tens = 10 tens + 7 tens = 1 hundred + 7 tens.
7*100 = 700 14*10 = 140 11*1 = 11 Sum = 851