given 1111
that would be in base10 20+ 21 + 22 + 23 = 1 + 2 + 4 + 8 = 15
you count using 2x and read right to left
given 1011
20 + 21 + 23 = 1 + 2 + 8 = 11
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XII-I-MMX
Four and eleven hundred two ten-thousandths
Assuming the question refers to Roman numerals, the answer is MMX.
Number systems used by ancient civilizations were not necessarily base 10. Roman numerals, for example, are base 5. Today most of the world uses Arabic numerals, which are base 10, but in the distant past different number systems were as common as different writing systems.
The X is ten. Two XX's would be twenty. Half an X, a V, would be five.