41 - 9, D16
No. It is not true to say 4000 is the smallest 4 digit number.
you say one number first then the other one for example 789 you say seven eight and then nine
odd because if the last digit before the decimal point is 1,3,5,7,9 it is odd and if it is 2,4,6,8,0 it is even Since 41 is not evenly divisible by 2, it is an odd number.
Its Impossible. I say this because anything that is three digits divided by a one digit number that equals 8 is not possible. For example the higher 1 digit number that you can multiply by eight is nine so I did 8x9 and got 72 which is not a three digit number. The lowest three digit number that 8 goes into is 104 which is 13x8 and 13 is not a one digit number. Therefore the problem is impossible. :)
41 - 9, D16
40
largest 5 digit number: 99999 3,3 99999/3/3=11111 11111/41=271 3, 3, 41, 271
A 22 digit number is called a quintillion.
The math works like this Lets call the original two digit number x, then adding a "3" to the right of x would translate into x*10+3 hence we have x = (10x +3) -372 x + 372 = 10x+3 372= 10x+3-x 372-3=10x-x 396 = 9x 396/9=x x=41 and if we test it, 41 with the added 3 would be 413 and 413 - 372 = 41 is true The original two digit number was 41
96, 85, 74, 63, 52, 41 or 30
100 quintillion is a 21 digit number with 20 zeroes.
41
It is: 3 and 41/50 as a mixed number in its lowest terms
No. It is not true to say 4000 is the smallest 4 digit number.
23 or 41
The largest 5-digit whole number is 99,999. Its prime factorization is: 3 x 3 x 41 x 271