If, as is normal, ab represents a times b, etc then
ab + ab + cc = 2ab + c2 which is generally not the same as abc.
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
Commutativity.
The existence of the additive inverse (of ab).
The square root of 149 (7 squared plus 10 squared equals 149).
Area = 0.5*AB*BC*sin(ABC) = 0.5*(2x+1)*(x+2)*0.5 = 3 So, (2x+1)*(x+2) = 12 2x2 + 5x + 2 = 12 2x2 + 5x - 10 = 0 x = 1.31 (to 3 sf)
i think its ABC and if that not right ask a teacher for the answer
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
You want: abc + ab Factor out the common terms which are "a" and "b" ab ( c + 1 )
yes because ab plus bc is ac
Oh, dude, you're hitting me with some math here. Okay, so, like, if you have "ab" plus "ab," you're basically just adding the same thing twice, so it's like adding two apples plus two apples - you end up with four apples. So, "ab" plus "ab" equals "2ab." Math can be weirdly simple sometimes, right?
Commutativity.
The existence of the additive inverse (of ab).
The square root of 149 (7 squared plus 10 squared equals 149).
Area = 0.5*AB*BC*sin(ABC) = 0.5*(2x+1)*(x+2)*0.5 = 3 So, (2x+1)*(x+2) = 12 2x2 + 5x + 2 = 12 2x2 + 5x - 10 = 0 x = 1.31 (to 3 sf)
associative property
It can be but need not be.
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