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To simplify the expression ((7 - 3i)(-11 + 5i)), use the distributive property (FOIL method). First, multiply the real parts: (7 \cdot -11 = -77). Next, multiply the outer parts: (7 \cdot 5i = 35i), then the inner parts: (-3i \cdot -11 = 33i), and finally the last parts: (-3i \cdot 5i = -15i^2). Combine the results: (-77 + 35i + 33i + 15) (since (i^2 = -1)) simplifies to (-62 + 68i). Thus, the simplified expression is (-62 + 68i).
What else can I help you with?
2 plus 5i plus 6 plus 3i?
I assume that "I" is a variable2+5i+6+3i7i+6+3i10i+616i is the answer
What does 7 plus 5i equal?
127
P and q are complex number's where p equals 2 plus 5i and q equals 6 minus i - find pq?
p = (2 + 5i)q = (6 - i)pq = (2 + 5i) (6 - i)pq = 12 + 30i - 2i - 5i2pq = 12 + 28i + 5pq = 17 + 28iIts the same as multiplying polynomials. Just multiply all the combinations of terms, group, and simplify.
Can x squared plus 25 be factored?
Not in real numbers. It can be factored to (x - 5i)(x + 5i) where i is the square root of negative one.
How do I simplify simplify 5 plus n-p plus 2n-4?
is eassy
What is the reciprocal of 3 plus 5i?
1/(3+5i)=(3-5i)/((3+5i)(3-5i))=(3-5i)/(9+25)=(3-5i)/34
What is the conjugate of the complex number 9 plus 5i?
9-5i
What is 1 divided by 2 plus 5i in the form a plus bi?
1/(2 + 5i) (multiply both the numerator and the denominator by 2 - 5i)= 1(2 - 5i)/(2 + 5i)(2 - 5i)= (2 - 5i)/(4 - 25i2) (substitute -1 for i2)= (2 - 5i)/(4 + 25)= (2 - 5i)/29= 2/29 - (5/29)i
2 plus 5i plus 6 plus 3i?
I assume that "I" is a variable2+5i+6+3i7i+6+3i10i+616i is the answer
How do you factor x squared plus 25?
(x-5i)(x+5i)
What is the conjugate of 11 plus 5i?
To find the complex conjugate change the sign of the imaginary part: For 11 + 5i the complex conjugate is 11 - 5i.
What is the complex conjugate of the following complex number 7 plus 5i?
The conjugate is 7-5i
What does 7 plus 5i equal?
127
P and q are complex number's where p equals 2 plus 5i and q equals 6 minus i - find pq?
p = (2 + 5i)q = (6 - i)pq = (2 + 5i) (6 - i)pq = 12 + 30i - 2i - 5i2pq = 12 + 28i + 5pq = 17 + 28iIts the same as multiplying polynomials. Just multiply all the combinations of terms, group, and simplify.
Can x squared plus 25 be factored?
Not in real numbers. It can be factored to (x - 5i)(x + 5i) where i is the square root of negative one.
How do you factor 9x squared plus 25?
9x2 + 25 has no rational factors. Its factorisation in the complex domain is:(3x + 5i)*(3x - 5i) where i is the imaginary square root of -1.
Complex conjugate of 5i?
0 + 5i Its complex conjugate is 0 - 5i
