To simplify the expression (2i \cdot 6u), you multiply the coefficients and combine the variables. This gives you (12iu). If there are no further simplifications or like terms to combine, the final simplified form is (12iu).
0.6-2i?
To solve this type of problem, multiply both the numerator and denominator by the conjugate of the denominator. (2 - 4i) / (4 + 2i) = (2 - 4i)(4 - 2i) / (4 + 2i)(4 - 2i) then expand all the terms, and simplify. = (8 - 20i + 8i2) / (16 - 4i2) = (8 - 20i - 8) / (16 + 4) = -20i / 20 = -i Which in the required answer format becomes, 0 + i.
-12 = 4 x 3 x -1 so sqrt = 2i root 3
When dividing complex numbers you must:Write the problem in fractional formRationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.You must remember that a complex number times its conjugate will give a real number.a complex number 2+2i. the conjugate to this is 2-i1. Multiply both together gives a real number.(2+2i)(2-2i) = 4 -4i + 4i + (-4i2) (and as i2 = -1) = 8To divide a complex number by a real number simply divide the real parts by the divisor.(8+4i)/2 = (4+2i)To divide a real number by a complex number.1. make a fraction of the expression 8/(2+2i)2. multiply by 1. express 1 as a fraction of the divisor's conjunction. 8/(2+2i)*(2-2i)/(2-2i)3. multiply numerator by numerator and denominator by denominator.(16-16i)/84. and simplify 2-2i
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i
0.6-2i?
(3+2i)-(3+2i)
6u = 222u = 222/6u = 37
4u2 - 6u - 39 does not have rational factors.
To solve this type of problem, multiply both the numerator and denominator by the conjugate of the denominator. (2 - 4i) / (4 + 2i) = (2 - 4i)(4 - 2i) / (4 + 2i)(4 - 2i) then expand all the terms, and simplify. = (8 - 20i + 8i2) / (16 - 4i2) = (8 - 20i - 8) / (16 + 4) = -20i / 20 = -i Which in the required answer format becomes, 0 + i.
24uv + 35u2 - 30u3 - 28v = 24uv - 28v - 30u3 + 35u2 = 4v*(6u - 7) - 5u2(6u - 7) = (4v - 5u2)*(6u - 7)
i meant 9+-12u+4+6u>-5, but wiki keeps changining it
-12 = 4 x 3 x -1 so sqrt = 2i root 3
This is calculated as follows: (2i)2 = 2i x 2i = 4i2 = 4(-1) = -4.
It is 6+2i. But -6-2i will also serve.
1/2i
6u