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How do you simplify i plus 6i?
answer is 7i, since its the same thing as: i + (i + i + i + i + i + i)
What is the solution for X squared plus 49 equals 0?
It'll be a complex number, denoted by 7i, where the number i is defined to be equal to the square root of -1.
What is x2 plus 49?
x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.
What is the complex conjugate of a plus bi?
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
What is the simplest of 60 140?
60 over 140 in simplest form is 2/7My work:60 divided by 20 = 3140 divided by 20 = 7i hope this helps
Write the complex number 2 - i divided by 5 plus i in the usual a plus bi form?
7
How do you do the math problem (4-3i)(5 2i)?
To multiply complex numbers you can use the same FOIL rule that you use for multiplying binomials (First, Inside, Outside, Last).(4 - 3i)(5 + 2i) = (4)(5) +(4)(2i) - (3i)(5) - (3i)(2i) = 20 + 8i-15i - 6(i)^2= 20 -7i - 6(-1) = 20 + 6 -7i = 26 -7i.
What is the complex conjugate of -5 plus 7i?
-5 - 7i
What are orthogonal pairs a 3i 2j b you j c 2i-3j d 7i j?
3i+2j)*(2i-3j)=0 bcz dot product is zero.
What does -7 divided by 3i equal?
-10
How do you simplify i plus 6i?
answer is 7i, since its the same thing as: i + (i + i + i + i + i + i)
What is the solution for X squared plus 49 equals 0?
It'll be a complex number, denoted by 7i, where the number i is defined to be equal to the square root of -1.
What is x2 plus 49?
x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.
Express this complex number in standard form i x sum of 5 plus 2i x sum of i-1?
i(2i+5)(i-1) [I hope I've interpreted this correctly - WikiAnswers does not make it easy to pose mathematical questions!] First of all, multiply out in ordinary fashion: i(2i+5)(i-1) = i(2i2 + 3i - 5) = 2i3 + 3i2 - 5i Now, i is defined in this way: i2 = -1 Multiplying both sides by i we get: i3 = -i Substitute this information into the expression: 2i3 + 3i2 - 5i = -2i - 3 - 5i = -3 - 7i Done. ---- As the exponent of i is raised, incidentally, you will observe a cycle like this: i, -1, -i, 1, i, -1...
What is the complex conjugate of a plus bi?
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
Find the conjugate of -4-7i?
It is -4+7i or +4-7i. All that is required is to change one of the signs, it does not matter which.
What is the simplest of 60 140?
60 over 140 in simplest form is 2/7My work:60 divided by 20 = 3140 divided by 20 = 7i hope this helps
