To simplify ( 3 \sqrt{432} ), first factor ( 432 ) into its prime factors: ( 432 = 2^4 \times 3^3 ). Then, rewrite the square root: ( \sqrt{432} = \sqrt{2^4 \times 3^3} = \sqrt{(2^2)^2 \times (3^1)^2 \times 3} = 2^2 \times 3 \times \sqrt{3} = 12\sqrt{3} ). Finally, multiply by ( 3 ): ( 3 \sqrt{432} = 3 \times 12\sqrt{3} = 36\sqrt{3} ).
sqrt(432) = sqrt(144*3) = sqrt(144)*sqrt(3) = 12*sqrt(3)
12x^2√5x
sqrt(27) = 3*sqrt(3).
The answer depends on the form of the radical expression.
There is no radical to simplify!
Radical 147 simplified is 7 radical 3. radical147= radical 49* radical 3 the square root of 49 is 7 therefore the answer is 7 radical 3
3^3*radical(128) = 3^3*radical(2^7) = 3^3*radical(2^6*2) =3^3*2^3*radical(2) = 216*radical(2).
12x^2√5x
sqrt(432) = sqrt(144*3) = sqrt(144)*sqrt(3) = 12*sqrt(3)
sqrt(27) = 3*sqrt(3).
294 is an integer and there is no sensible radical form for it.
5 root 3
The answer depends on the form of the radical expression.
4 times radical 34
radical 89 cannot be simplified.
√108 = √(36 x 3) = √36 x √3 = 6√3
There is no radical to simplify!