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To simplify ( 3 \sqrt{432} ), first factor ( 432 ) into its prime factors: ( 432 = 2^4 \times 3^3 ). Then, rewrite the square root: ( \sqrt{432} = \sqrt{2^4 \times 3^3} = \sqrt{(2^2)^2 \times (3^1)^2 \times 3} = 2^2 \times 3 \times \sqrt{3} = 12\sqrt{3} ). Finally, multiply by ( 3 ): ( 3 \sqrt{432} = 3 \times 12\sqrt{3} = 36\sqrt{3} ).

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AnswerBot

21h ago

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