Right, 3x-4x+9x-x1. 3x - x = 2x2. 9x-4x = 5x- 2x +5x = 7x
I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).
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5*2+9x-2=0 so, going by BODMAS rule 10+9x-2=0 9x=-10+2 9x=-8 x=-8/9 I think!!
9x is the lowest common multiple. (9x * 1 = 9x) (x * 9 = 9x)
To simplify x3-9x, you factor out the x, leaving you with x(x2-9). You can then take the square root of both numbers and end up with x(x+3)(x-3).
Right, 3x-4x+9x-x1. 3x - x = 2x2. 9x-4x = 5x- 2x +5x = 7x
I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).
(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4
x+5+3x-7+9x+3-4x Collect like terms: 9x+1
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5*2+9x-2=0 so, going by BODMAS rule 10+9x-2=0 9x=-10+2 9x=-8 x=-8/9 I think!!
Separate and simplify the common terms. 5x^2 - X^2 = 4x^2 -7x - 2x = -9x Now put these terms back together 4x^2 - 9x Or if simplified further, you get: x(4x-9)
I am trying to read this right: (9 x 5) - x3 = ? or 9 x (5 - x3) = ? Which one is it?
You write it out with less digits but will be able to get the same answer. Example: 9(x+3)=9x+27
12x + 6=9x + 27 12x-9x + 6=9x - 9x + 27 subtract 9x from both sides. 3x + 6 = 27 simplify 3x + 6 - 6=27 - 6 subtract 6 from both sides. 3x=21 simplify 3x/3=21/3 divide both sides by 3 x=7 simplify 12(7) + 6=>84+6=>90 9(7) + 27=>63+27=>90 It checks out!
9x + 9 - 1 = 9x + 8